Audio and Video All audio, video, alarms, and all other electronics

I replaced my 8" sub (again).

Thread Tools
 
Search this Thread
 
Old Mar 3, 2006 | 08:25 AM
  #1  
Navyflyer11's Avatar
Thread Starter
Senior Member
 
Joined: 02-23-2006
Posts: 629
From: Oklahoma
I replaced my 8" sub (again).

Well I broke down and replaced my 8" sub again. I pulled out the JL Audio 8W0 and put in an Kicker CVR8. I needed a speaker that could handle more power than the JL.

Here is the the box covered in Roadkill.

In order to get the CVR8 to seal right I installed a ring/spacer to ensure clearence.

here is the speaker installed with the Kicker badge.

Here is the rear befor the badge. I wired the CVR in parallel, it is a dual voice coil 4ohms each. Thuss making it a 2ohm load. Furter more the bridging module cuts the impedance in 1/2 making a total load of 1 omh. The Orion HCCA 225 I am using is stable down to a 1/2 ohm load. In that configuration I can get 400 watts easy.
Old Mar 3, 2006 | 08:28 AM
  #2  
adamlowery's Avatar
Senior Member
 
Joined: 09-11-2005
Posts: 829
From: McLoud, Oklahoma
We gotta meet up again. I wanna hear that baby.
Old Mar 3, 2006 | 08:32 AM
  #3  
Skatetheglobe's Avatar
Senior Member
 
Joined: 01-29-2006
Posts: 1,148
From: Port Saint Lucie,Florida
All that ohm stuff confuses me.
Old Mar 3, 2006 | 08:41 AM
  #4  
captain howdy's Avatar
Banned
 
Joined: 10-14-2005
Posts: 9,121
From: Rochester,N.Y.
Originally Posted by Skatetheglobe
All that ohm stuff confuses me.
Do you want an explanation of Ohm's law?
Old Mar 3, 2006 | 08:44 AM
  #5  
Navyflyer11's Avatar
Thread Starter
Senior Member
 
Joined: 02-23-2006
Posts: 629
From: Oklahoma
I thought you were asking me for a moment.
Old Mar 3, 2006 | 10:07 AM
  #6  
captain howdy's Avatar
Banned
 
Joined: 10-14-2005
Posts: 9,121
From: Rochester,N.Y.
Originally Posted by Navyflyer11
I thought you were asking me for a moment.
Nah, obviously you understand. :)
Old Mar 3, 2006 | 10:17 AM
  #7  
Skatetheglobe's Avatar
Senior Member
 
Joined: 01-29-2006
Posts: 1,148
From: Port Saint Lucie,Florida
Go for it!
Old Mar 3, 2006 | 10:31 AM
  #8  
captain howdy's Avatar
Banned
 
Joined: 10-14-2005
Posts: 9,121
From: Rochester,N.Y.
I am going to simplify things and not get into formulas or anything. Basically it is a measurement of electical resistance on the line. A more technical definition would be it is a law that definines the relationship between power, voltage, current, and resistance. Basically in a nut shell the less resistance between the amp and your speakers the more efficiently they will opperate.
Old Mar 3, 2006 | 10:38 AM
  #9  
AlienHHR's Avatar
Senior Member
 
Joined: 02-06-2006
Posts: 297
From: Raleigh, NC
I=v*r

*** Strange... I posted the formula before CH's reply, but it showed up 7 minutes after??? ***

Another note: Resistance in series adds up, while in parallel it divides. Example: Two 4 ohm speakers wired in series will present an 8 ohm load to the amp. Two 4 ohm speakers wired in parallel will present a 2 ohm load to the amp.
Old Mar 3, 2006 | 10:40 AM
  #10  
captain howdy's Avatar
Banned
 
Joined: 10-14-2005
Posts: 9,121
From: Rochester,N.Y.
There is the formula. :)



All times are GMT -5. The time now is 02:01 AM.